8/4/2023 0 Comments Add days to date python![]() ![]() from datetime import timedelta, date twodaysinfuture date.today () + timedelta (days2) print (date. With these in your toolbox you're 90% of the way toward solving all of the date and time challenges in your next python project. To add days to date using Python, the easiest way is to use the Python timedelta () function from the datetime module. So now you are armed with the five most useful datetime tricks. Be prepared to perform some twisted conversions in order to get all of the data you ingest into that format. However, be warned that there exist a multitude of a date formats in the wild. I highly recommend whenever you are given the choice to format your dates in this way for ease of interpretability and compatibility. (An international standard, ISO 8601, established this in 1988.) In this format, for example, Jwould be ''. In this code snippet, '%Y' represents the year, '%m' the two digit month, and '%d' the two digit day.Īs a side note, there is actually one correct way to represent years, months, and days in dates: 'YYYY-MM-DD'. When making a conversion in either direction, we have to supply a string that specifies the format. To do this, we use the strptime() and strftime() functions. It is also helpful when we want to expose our datetime object to a user, or export it to a text file. This is particularly helpful when we are ingesting data from a text file, and want to turn text dates into datetime objects. New_datetime = (ĭatestr = new_datetime.strftime('%Y-%m-%d')įinally, we come to trick number five, which is converting a date to and from a string. # Pass a date string and a code for interpreting it. The first datetime references the package, the second datetime references the module, and combine() is a function within that module. So when we combine our date and time, we call it with the apparently redundant datetime.datetime prefix. Datetime is the name of the package, a module within the package, and the object. We use the combine() function, and pass it the date object and the time object that we want to build our datetime out of.īecause of the naming convention, calls to datetime can be confusing. Then we create a date by passing the year, month, and day.Ĭreating a datetime is straightforward. Because we didn’t supply the second or the microsecond, these are assumed to be zero. We start by creating a time, passing it the hour of 7 and the minute 0. The first trick for working with datetimes is to be able to create them by combining date and time objects. The above approach operates in the same amount of time, no matter how many days you have.Start_datetime = ( Keep in mind that, if you want to add 500 days to a date, you will go through a loop and make the same set of computations 500 times. Return start_date + timedelta(days=total_days)Įven though this does not fully solves your problem, I wanted to let it here because the solutions found on the internet for adding working days to dates, all of them have O(n) complexity. This is the best solution because it has O(1) complexity (no loop) and no 3-rd party, but it does not take into account the holidays: def add_working_days_to_date(self, start_date, days_to_add): # increment using recursion to compensate for weekends # only work with holidays up to and including the current new_date. :return: the new date wroking_days date from now :type holidays: iter(datetime.date|datetime.datetime) :param holidays: iterator of datetime.datetime of datetime.date instances :param working_days: offset in working days you want to add (can be negative) :type start: datetime.datetime|datetime.date ![]() def add_working_days(start, working_days, holidays=()):Īdd working_days to start start date, skipping weekends and holidays. Also, holidays only works when the offset is positive. ![]()
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